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((1/12)*x^2-1)'The calculation above is a derivative of the function f (x)
((1/12)*x^2)'+(-1)'
(1/12)*(x^2)'+(1/12)'*x^2+(-1)'
(1/12)*(x^2)'+0*x^2+(-1)'
(1/12)*2*x^(2-1)+0*x^2+(-1)'
(1/12)*2*x+0*x^2+(-1)'
1/6*x+0
(1/6)*x
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